§ Задание 26
\[\boxed{\text{6.26.}}\]
\[\textbf{а)}\ 13\frac{3}{4} > 12\frac{1}{4}\]
\[\textbf{б)}\ 6\frac{2}{3} = 6\frac{2}{3}\ \]
\[\textbf{в)}\ 9\frac{17}{25} < 9\frac{19}{25}\text{\ \ \ }\]
\[\boxed{\text{6.26.}}\]
\[\textbf{а)}\ 13\frac{3}{4} > 12\frac{1}{4}\]
\[\textbf{б)}\ 6\frac{2}{3} = 6\frac{2}{3}\ \]
\[\textbf{в)}\ 9\frac{17}{25} < 9\frac{19}{25}\text{\ \ \ }\]