2) $$(2,5 - 0,75) \cdot \frac{4}{7} + [(3\frac{3}{8} - 2\frac{11}{12}) \cdot 1\frac{7}{9} + 2\frac{11}{12} \cdot 1\frac{7}{9}] : (3,5 : 2\frac{2}{3});$$
Выполним действия в скобках:
$$2,5 - 0,75 = 1,75 = \frac{175}{100} = \frac{7}{4}$$
$$3\frac{3}{8} = \frac{27}{8}$$
$$2\frac{11}{12} = \frac{35}{12}$$
$$\frac{27}{8} - \frac{35}{12} = \frac{81}{24} - \frac{70}{24} = \frac{11}{24}$$
$$1\frac{7}{9} = \frac{16}{9}$$
$$\frac{11}{24} \cdot \frac{16}{9} = \frac{11 \cdot 2}{3 \cdot 9} = \frac{22}{27}$$
$$\frac{35}{12} \cdot \frac{16}{9} = \frac{35 \cdot 4}{3 \cdot 9} = \frac{140}{27}$$
$$\frac{22}{27} + \frac{140}{27} = \frac{162}{27} = 6$$
$$3,5 : 2\frac{2}{3} = 3,5 : \frac{8}{3} = \frac{7}{2} \cdot \frac{3}{8} = \frac{21}{16}$$
$$6 : \frac{21}{16} = 6 \cdot \frac{16}{21} = 2 \cdot \frac{16}{7} = \frac{32}{7}$$
$$\frac{7}{4} \cdot \frac{4}{7} = 1$$
$$1 + \frac{32}{7} = \frac{7}{7} + \frac{32}{7} = \frac{39}{7} = 5\frac{4}{7}$$
Ответ: $$5\frac{4}{7}$$