4.\frac{2}{5}+2\frac{1}{2}:[(7\frac{5}{12}-5\frac{3}{4}):22\frac{1}{2}+10\frac{5}{18}]-\frac{4}{5}

4.\frac{2}{5}+2\frac{1}{2}:[(7\frac{5}{12}-5\frac{3}{4}):22\frac{1}{2}+10\frac{5}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[(\frac{89}{12}-\frac{23}{4}):\frac{45}{2}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[(\frac{89}{12}-\frac{69}{12}):\frac{45}{2}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{20}{12}:\frac{45}{2}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{5}{3}:\frac{45}{2}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{5}{3}\cdot\frac{2}{45}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{2}{3}\cdot\frac{1}{9}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{2}{27}+\frac{185}{18}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:[\frac{4}{54}+\frac{555}{54}]-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}:\frac{559}{54}-\frac{4}{5}=\frac{2}{5}+\frac{5}{2}\cdot\frac{54}{559}-\frac{4}{5}=\frac{2}{5}+\frac{5}{1}\cdot\frac{27}{559}-\frac{4}{5}=\frac{2}{5}+\frac{135}{559}-\frac{4}{5}=\frac{1118}{2795}+\frac{675}{2795}-\frac{2236}{2795}=\frac{1118+675-2236}{2795}=\frac{-443}{2795}=-0,1585