5. Найдите значение выражения: a) ((($$\frac{5}{6}$$-$$\frac{3}{8}$$)\cdot\frac{8}{33}$$+$$\frac{1}{3}$$):($$\frac{6\frac{35}{84}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$; б) $$\frac{\frac{3}{5}+\frac{5}{21}+\frac{15}{28}:\frac{5}{84}}{\frac{5}{1}:\frac{1}{2}+10}$$ + $$\frac{2:\frac{1}{2}+3:1}{\frac{1}{2}:2+1:\frac{3}{2}}$$\cdot\frac{1}{36}$$-1$$\frac{16}{35}$$; в) $$\frac{8:(3:(2\frac{3}{4}-1\frac{15}{28})+\frac{2}{3}:\frac{3}{2})+\frac{57}{223}}{14\cdot(5\frac{5}{7}-4\frac{3}{4})-9\frac{5}{7}+\frac{3}{13}}$$; г) $$\frac{(\frac{5}{1}\frac{1}{84}+\frac{31}{63}-(\frac{2}{252}^{31}+\frac{3}{21}))}{(\frac{15}{26}+\frac{1}{39}-\frac{7}{156}):(20\frac{1}{4}:26)}$$\cdot(24:(1\frac{1}{2}:4\frac{3}{8}))$$; д) $$(7\frac{332}{405}-5\frac{890}{891}-(1\frac{488}{495}-\frac{98}{99})):(10-8\frac{151}{198})$$.

a) ((($$\frac{5}{6}$$-$$\frac{3}{8}$$)\cdot\frac{8}{33}$$+$$\frac{1}{3}$$):($$\frac{6\frac{35}{84}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$ = ((($$\frac{20}{24}$$-$$\frac{9}{24}$$)\cdot\frac{8}{33}$$+$$\frac{1}{3}$$):($$\frac{6\frac{5}{12}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(($$\frac{11}{24}$$\cdot\frac{8}{33}$$+$$\frac{1}{3}$$):($$\frac{6\frac{5}{12}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{1}{9}$$+\frac{1}{3}$$):($$\frac{6\frac{5}{12}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{1}{9}$$+\frac{3}{9}$$):($$\frac{6\frac{5}{12}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{6\frac{5}{12}+8\frac{17}{56}-12\frac{1}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{\frac{77}{12}+\frac{465}{56}-\frac{97}{8}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{\frac{539}{84}+\frac{345}{56}-\frac{679}{56}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{\frac{1617}{252}+\frac{1552}{252}-\frac{2401}{252}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{768}{252}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):($$\frac{64}{21}}{-\frac{11}{1635}}$$)\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):(\frac{64}{21}$$\cdot\frac{-1635}{11})\cdot36\frac{1}{3}$$=(\frac{4}{9}$$):(\frac{64}{7}$$\cdot\frac{-545}{11})\cdot36\frac{1}{3}$$=(\frac{4}{9})$$:(\frac{-34880}{77})\cdot\frac{109}{3}=(\frac{4}{9})\cdot(\frac{-77}{34880})\cdot\frac{109}{3}=(\frac{4}{9})\cdot(\frac{-77}{34880})\cdot\frac{109}{3}=-\frac{4\cdot77\cdot109}{9\cdot34880\cdot3}=-\frac{33628}{941760}=-\frac{8407}{235440}$$

Ответ: -$$\frac{8407}{235440}$$

б) $$\frac{\frac{3}{5}+\frac{5}{21}+\frac{15}{28}:\frac{5}{84}}{\frac{5}{1}:\frac{1}{2}+10}$$ + $$\frac{2:\frac{1}{2}+3:1}{\frac{1}{2}:2+1:\frac{3}{2}}$$\cdot\frac{1}{36}$$-1$$\frac{16}{35}$$

в) $$\frac{8:(3:(2\frac{3}{4}-1\frac{15}{28})+\frac{2}{3}:\frac{3}{2})+\frac{57}{223}}{14\cdot(5\frac{5}{7}-4\frac{3}{4})-9\frac{5}{7}+\frac{3}{13}}$$;

г) $$\frac{(\frac{5}{1}\frac{1}{84}+\frac{31}{63}-(\frac{2}{252}^{31}+\frac{3}{21}))}{(\frac{15}{26}+\frac{1}{39}-\frac{7}{156}):(20\frac{1}{4}:26)}$$\cdot(24:(1\frac{1}{2}:4\frac{3}{8}))$$;

д) $$(7\frac{332}{405}-5\frac{890}{891}-(1\frac{488}{495}-\frac{98}{99})):(10-8\frac{151}{198})$$.