3. 11$$\frac{2}{5}$$+7$$\frac{1}{2}\cdot(285$$\frac{3}{5}$$:14$$\frac{1}{2}$$-1$$\frac{23}{30}$$+\frac{13}{50}):(24$$\frac{5}{18}$$-10$$\frac{23}{100}$$)

3. 11$$\frac{2}{5}$$+7$$\frac{1}{2}\cdot(285$$\frac{3}{5}$$:14$$\frac{1}{2}$$-1$$\frac{23}{30}$$+\frac{13}{50}):(24$$\frac{5}{18}$$-10$$\frac{23}{100}$$)=\frac{57}{5}+\frac{15}{2}\cdot(\frac{1428}{5}:\frac{29}{2}-\frac{53}{30}+\frac{13}{50}):(\frac{437}{18}-\frac{1023}{100})=\frac{57}{5}+\frac{15}{2}\cdot(\frac{1428}{5}\cdot\frac{2}{29}-\frac{53}{30}+\frac{13}{50}):(\frac{21850}{900}-\frac{9207}{900})=\frac{57}{5}+\frac{15}{2}\cdot(\frac{1428}{5}\cdot\frac{2}{29}-\frac{53}{30}+\frac{13}{50}):\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot(\frac{2856}{145}-\frac{265}{150}+\frac{39}{150}):\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot(\frac{2856}{145}-\frac{226}{150}):\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot(\frac{419010}{21750}-\frac{32770}{21750}):\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot\frac{386240}{21750}:\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot\frac{38624}{2175}:\frac{12643}{900}=\frac{57}{5}+\frac{15}{2}\cdot\frac{38624}{2175}\cdot\frac{900}{12643}=\frac{57}{5}+\frac{15\cdot38624\cdot900}{2\cdot2175\cdot12643}=\frac{57}{5}+\frac{521424000}{55099350}=\frac{57}{5}+9,4632...=11,4+9,4632=20,8632...

Ответ: 20,8632...