2°. Выполните действия: 1) \(\frac{24}{37}-\frac{8}{37}+\frac{11}{37}\); 3) \(1-\frac{7}{15}\); 2) \(3\frac{7}{11}+6\frac{3}{11}-5\frac{5}{11}\); 4) \(5\frac{3}{8}-2\frac{5}{8}\).

1) \(\frac{24}{37}-\frac{8}{37}+\frac{11}{37} = \frac{24-8+11}{37} = \frac{16+11}{37} = \frac{27}{37}\)

2) \(3\frac{7}{11}+6\frac{3}{11}-5\frac{5}{11} = (3+6-5) + (\frac{7}{11} + \frac{3}{11} - \frac{5}{11}) = 4 + \frac{7+3-5}{11} = 4 + \frac{5}{11} = 4\frac{5}{11}\)

3) \(1-\frac{7}{15} = \frac{15}{15} - \frac{7}{15} = \frac{15-7}{15} = \frac{8}{15}\)

4) \(5\frac{3}{8}-2\frac{5}{8} = 5\frac{3}{8}-2\frac{5}{8} = 4\frac{11}{8} - 2\frac{5}{8} = (4-2) + (\frac{11}{8} - \frac{5}{8}) = 2 + \frac{11-5}{8} = 2 + \frac{6}{8} = 2\frac{6}{8} = 2\frac{3}{4}\)

Ответ: 1) \(\frac{27}{37}\); 2) \(4\frac{5}{11}\); 3) \(\frac{8}{15}\); 4) \(2\frac{3}{4}\)