1.101. Көрсетілген амалды орындаңдар: 1) \((\sqrt{20}-\sqrt5)\cdot\sqrt5\); 2) \(\sqrt3(\sqrt{12}+\sqrt3)\); 3) \((\sqrt7-2)(\sqrt7+2)\); 4) \((\sqrt8-\sqrt5)(\sqrt8+\sqrt5)\).

1. \((\sqrt{20}-\sqrt5)\cdot\sqrt5=\sqrt{100}-\sqrt{25}=10-5=5\).
2. \(\sqrt3(\sqrt{12}+\sqrt3)=\sqrt{36}+\sqrt9=6+3=9\).
3. \((\sqrt7-2)(\sqrt7+2)=7-4=3\).
4. \((\sqrt8-\sqrt5)(\sqrt8+\sqrt5)=8-5=3\).

Жауабы: 1) 5; 2) 9; 3) 3; 4) 3.