Ответ:

а) \(\sqrt2-\dfrac{10}{\sqrt2}=\sqrt2-5\sqrt2=-4\sqrt2\).

б) \(\dfrac{15}{\sqrt5}+7\sqrt5=3\sqrt5+7\sqrt5=10\sqrt5\).

в) \(\left(\dfrac{12}{\sqrt3}-\sqrt3\right)\cdot\sqrt3=(4\sqrt3-\sqrt3)\cdot\sqrt3=3\sqrt3\cdot\sqrt3=9\).