Вопрос:
1 С-29. Решение уравнений
1. Решите уравнение:
1) a) (3x+5) + (8x + 1) = 17;
6) 19 - 5(3x - 1) = 9;
2) a) 30+5(3x-1) = 35х - 25;
6) 10x - 5 = 6(8x + 3) -5х;
3) a) 6(8x + 5) = 0;
6) 6(8x + 5) = -6;
в) (3-5,8x) - (2,2x + 3) = 16;
г) 21 = -20-8(2x – 0,5);
в) -10(3-4x) +51 = 7(5x + 3);
г) 6x – 5(3x + 2) = 5(x - 1) -8;
в) -8(2х0,5) = 0;
г) -8(2х -0,5) = -8.
Ответ:
1. Решите уравнение:
- 1) a) (3x+5) + (8x + 1) = 17
\( 3x + 5 + 8x + 1 = 17 \)
\( 11x + 6 = 17 \)
\( 11x = 11 \)
\( x = 1 \)
- 6) 19 - 5(3x - 1) = 9
\( 19 - 15x + 5 = 9 \)
\( 24 - 15x = 9 \)
\( -15x = 9 - 24 \)
\( -15x = -15 \)
\( x = 1 \)
- 2) a) 30+5(3x-1) = 35х - 25
\( 30 + 15x - 5 = 35x - 25 \)
\( 25 + 15x = 35x - 25 \)
\( 25 + 25 = 35x - 15x \)
\( 50 = 20x \)
\( x = \frac{50}{20} = \frac{5}{2} = 2,5 \)
- 6) 10x - 5 = 6(8x + 3) -5х
\( 10x - 5 = 48x + 18 - 5x \)
\( 10x - 5 = 43x + 18 \)
\( 10x - 43x = 18 + 5 \)
\( -33x = 23 \)
\( x = -\frac{23}{33} \)
- 3) a) 6(8x + 5) = 0
\( 8x + 5 = 0 \)
\( 8x = -5 \)
\( x = -\frac{5}{8} \)
- 6) 6(8x + 5) = -6
\( 8x + 5 = -1 \)
\( 8x = -6 \)
\( x = -\frac{6}{8} = -\frac{3}{4} \)
- в) (3-5,8x) - (2,2x + 3) = 16
\( 3 - 5,8x - 2,2x - 3 = 16 \)
\( -8x = 16 \)
\( x = -2 \)
- г) 21 = -20-8(2x – 0,5)
\( 21 = -20 - 16x + 4 \)
\( 21 = -16 - 16x \)
\( 21 + 16 = -16x \)
\( 37 = -16x \)
\( x = -\frac{37}{16} \)
- в) -10(3-4x) +51 = 7(5x + 3)
\( -30 + 40x + 51 = 35x + 21 \)
\( 21 + 40x = 35x + 21 \)
\( 40x - 35x = 21 - 21 \)
\( 5x = 0 \)
\( x = 0 \)
- г) 6x – 5(3x + 2) = 5(x - 1) -8
\( 6x - 15x - 10 = 5x - 5 - 8 \)
\( -9x - 10 = 5x - 13 \)
\( -9x - 5x = -13 + 10 \)
\( -14x = -3 \)
\( x = \frac{3}{14} \)
- в) -8(2х0,5) = 0
\( -8(1x) = 0 \)
\( -8x = 0 \)
\( x = 0 \)
- г) -8(2х -0,5) = -8
\( 2x - 0,5 = 1 \)
\( 2x = 1 + 0,5 \)
\( 2x = 1,5 \)
\( x = \frac{1,5}{2} = 0,75 \)
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