1. Сокращение дробей:
- \(\text{а)}\quad\frac{14a^3b^5}{21a^4b} = \frac{2 \cdot 7 \cdot a^3 \cdot b^5}{3 \cdot 7 \cdot a^4 \cdot b} = \frac{2b^4}{3a}\)
- \(\text{б)}\quad\frac{x^2+x}{x^2} = \frac{x(x+1)}{x^2} = \frac{x+1}{x}\)
- \(\text{в)}\quad\frac{a+2b}{a^2-4b^2} = \frac{a+2b}{(a-2b)(a+2b)} = \frac{1}{a-2b}\)
Ответ: а) \(\frac{2b^4}{3a}\); б) \(\frac{x+1}{x}\); в) \(\frac{1}{a-2b}\).