Ответ:

Вариант А1.

  1. \(\dfrac{2xy^3}{8x^2y^2}=\dfrac{y}{4x}\).
  2. \(\dfrac{3x^2+9x}{3x}=\dfrac{3x(x+3)}{3x}=x+3\).
  3. \(\dfrac{a-3}{a^2-6a+9}=\dfrac{a-3}{(a-3)^2}=\dfrac1{a-3}\).

Вариант А2.

  1. \(\dfrac{3x^4y}{9x^3y^2}=\dfrac{x}{3y}\).
  2. \(\dfrac{2x^2-6x}{2x}=\dfrac{2x(x-3)}{2x}=x-3\).
  3. \(\dfrac{a+1}{a^2+2a+1}=\dfrac{a+1}{(a+1)^2}=\dfrac1{a+1}\).

Ответ: А1: а) \(\dfrac{y}{4x}\); б) \(x+3\); в) \(\dfrac1{a-3}\). А2: а) \(\dfrac{x}{3y}\); б) \(x-3\); в) \(\dfrac1{a+1}\).