1. Вычислите: 1) \(\frac{2}{17}-\frac{8}{17}\); 2) \(3687-\frac{6}{29}\); 3) \(6\frac{1}{7}-9\frac{1}{11}\).

1. \(\frac{2}{17}-\frac{8}{17}=\frac{2-8}{17}=-\frac{6}{17}\).
2. \(3687-\frac{6}{29}=3686+\frac{23}{29}=3686\frac{23}{29}\).
3. \(6\frac{1}{7}=\frac{43}{7}=\frac{473}{77}\), \(9\frac{1}{11}=\frac{100}{11}=\frac{700}{77}\).
   \(\frac{473}{77}-\frac{700}{77}=-\frac{227}{77}=-2\frac{73}{77}\).

Ответ: 1) \(-\frac{6}{17}\); 2) \(3686\frac{23}{29}\); 3) \(-2\frac{73}{77}\).