1. Вычислите: а) \(5\frac{7}{12}+1\frac{1}{3}\); б) \(6\frac{3}{50}-3\frac{17}{75}\); в) \(5\frac{6}{55}+3\frac{9}{44}-4\frac{7}{22}\).

1. \(5\frac{7}{12}+1\frac{1}{3}=5\frac{7}{12}+1\frac{4}{12}=6\frac{11}{12}\).
2. \(6\frac{3}{50}-3\frac{17}{75}=\frac{3003}{500}-\frac{2267}{75}=\frac{2327}{750}\).
3. \(5\frac{6}{55}+3\frac{9}{44}-4\frac{7}{22}=\frac{281}{55}+\frac{141}{44}-\frac{95}{22}=\frac{1124+705-950}{220}=\frac{879}{220}=3\frac{219}{220}\).

Ответ: а) \(6\frac{11}{12}\); б) \(\frac{2327}{750}=3\frac{77}{750}\); в) \(3\frac{219}{220}\).