1. Вычислите: a) (\(-\frac{1}{4}\))^-3 ⋅ (\(-4\))⁰; б) \(\frac{3^{-3} ⋅ 9^{-3}}{(-27)^{-2}}\); в) (\(\frac{2}{3}\))^-1 + (\(1\frac{2}{7}\))^-2 ⋅ ((\-3,4)⁰ + (\(-1\))^-2).

1. Вычисление выражений:

1. а) \( \left(-\frac{1}{4}\right)^{-3} \cdot \left(-4\right)^{0} = \left(-4\right)^{3} \cdot 1 = -64 \cdot 1 = -64 \)
2. б) \( \frac{3^{-3} \cdot 9^{-3}}{(-27)^{-2}} = \frac{\frac{1}{3^3} \cdot \frac{1}{9^3}}{\frac{1}{(-27)^2}} = \frac{\frac{1}{27} \cdot \frac{1}{729}}{\frac{1}{729}} = \frac{1}{27} \)
3. в) \( \left(\frac{2}{3}\right)^{-1} + \left(1\frac{2}{7}\right)^{-2} \cdot \left( (-3.4)^{0} + (-1)^{-2} \right) = \frac{3}{2} + \left(\frac{9}{7}\right)^{-2} \cdot \left(1 + 1\right) = \frac{3}{2} + \left(\frac{7}{9}\right)^{2} \cdot 2 = \frac{3}{2} + \frac{49}{81} \cdot 2 = \frac{3}{2} + \frac{98}{81} = \frac{3 \cdot 81 + 98 \cdot 2}{162} = \frac{243 + 196}{162} = \frac{439}{162} \)

Ответ: а) -64; б) \(\frac{1}{27}\); в) \(\frac{439}{162}\).