\[ (2x - 5)^2 = (3x + 1)^2 \]
\[ 2x - 5 = 3x + 1 \quad \text{или} \quad 2x - 5 = -(3x + 1) \]
\[ 2x - 5 = 3x + 1 \]
\[ 2x - 3x = 1 + 5 \]
\[ -x = 6 \]
\[ x = -6 \]
\[ 2x - 5 = -3x - 1 \]
\[ 2x + 3x = -1 + 5 \]
\[ 5x = 4 \]
\[ x = \frac{4}{5} \]
Ответ: -6; 4/5