Ответ:
y' = (6^{x^2})'(2 - x) + 6^{x^2}(2 - x)'
y' = \(6^{x^2} \ln 6 \cdot 2x\)(2 - x) + 6^{x^2}(-1) = 6^{x^2}[2x(2 - x)\(\ln\) 6 - 1]
y' = (6^{x^2})'(2 - x) + 6^{x^2}(2 - x)'
y' = \(6^{x^2} \ln 6 \cdot 2x\)(2 - x) + 6^{x^2}(-1) = 6^{x^2}[2x(2 - x)\(\ln\) 6 - 1]