\[ 2\frac{3}{5} = \frac{2 \times 5 + 3}{5} = \frac{13}{5} \]
\[ \frac{13}{5} \times \frac{2}{13} = \frac{13 \times 2}{5 \times 13} = \frac{2}{5} \]
\[ \frac{5}{6} + \frac{3}{4} = \frac{5 \times 2}{6 \times 2} + \frac{3 \times 3}{4 \times 3} = \frac{10}{12} + \frac{9}{12} = \frac{19}{12} \]
\[ \frac{19}{12} : \frac{1}{6} = \frac{19}{12} \times \frac{6}{1} = \frac{19 \times 6}{12 \times 1} = \frac{19}{2} \]
\[ \frac{2}{5} - \frac{19}{2} \]
Приводим к общему знаменателю (10):
\[ \frac{2 \times 2}{5 \times 2} - \frac{19 \times 5}{2 \times 5} = \frac{4}{10} - \frac{95}{10} = \frac{4 - 95}{10} = \frac{-91}{10} \]
\[ \frac{-91}{10} = -9\frac{1}{10} \]
Ответ: -9,1