170. 1) $(3\frac{2}{5}\cdot2-5\frac{3}{4}:1\frac{11}{12}):3\frac{1}{6}-4\frac{4}{5}:9+2\frac{2}{3}$; 2) $[40-(4,25\cdot7,08+6,768:0,75)]\cdot2050$.

Question

Вопрос: $Фото задания: 170. 1) $(3\frac{2}{5}\cdot2-5\frac{3}{4}:1\frac{11}{12}):3\frac{1}{6}-4\frac{4}{5}:9+2\frac{2}{3}$; 2)…$ Фото задания

Accepted Answer

1) $3\frac{2}{5}\cdot2=\frac{34}{5}$, а $5\frac{3}{4}:1\frac{11}{12}=\frac{23}{4}:\frac{23}{12}=3$.

Тогда $(\frac{34}{5}-3):\frac{19}{6}=\frac{19}{5}\cdot\frac{6}{19}=\frac{6}{5}$.

$\frac{6}{5}-\frac{24}{5}:9+\frac{8}{3}=\frac{6}{5}-\frac{8}{15}+\frac{8}{3}=\frac{10}{3}$.

2) $4,25\cdot7,08=30,09$, $6,768:0,75=9,024$.

$[40-(30,09+9,024)]\cdot2050=0,886\cdot2050=1816,3$.

Ответ: 1) $\frac{10}{3}$; 2) $1816,3$.

170. 1) \((3\frac{2}{5}\cdot2-5\frac{3}{4}:1\frac{11}{12}):3\frac{1}{6}-4\frac{4}{5}:9+2\frac{2}{3}\); 2) \([40-(4,25\cdot7,08+6,768:0,75)]\cdot2050\).