2.322. Вычислите: а) (1 1/2)³ − 2 1/3 · 1 1/4; б) 4/9 · (3 3/14 · 2 4/5)²; в) ((2/3)³ + 5/9) · 9/11; г) (2 1/2 − 11/14)(1 4/9 + 2 5/6 − 2 3/4).

а) \(\left(1\frac{1}{2}\right)^3-2\frac{1}{3}\cdot1\frac{1}{4}=\frac{27}{8}-\frac{7}{3}\cdot\frac{5}{4}=\frac{81}{24}-\frac{70}{24}=\frac{11}{24}\).

б) \(\frac{4}{9}\left(3\frac{3}{14}\cdot2\frac{4}{5}\right)^2=\frac{4}{9}\left(\frac{45}{14}\cdot\frac{14}{5}\right)^2=\frac{4}{9}\cdot9^2=36\).

в) \(\left(\left(\frac{2}{3}\right)^3+\frac{5}{9}\right)\cdot\frac{9}{11}=\left(\frac{8}{27}+\frac{15}{27}\right)\cdot\frac{9}{11}=\frac{23}{33}\).

г) \(2\frac{1}{2}-\frac{11}{14}=\frac{12}{7}\), а \(1\frac{4}{9}+2\frac{5}{6}-2\frac{3}{4}=\frac{55}{36}\). Тогда \(\frac{12}{7}\cdot\frac{55}{36}=\frac{55}{21}=2\frac{13}{21}\).

Ответ: а) 11/24; б) 36; в) 23/33; г) 2 13/21.