Ответ:
а) \(\frac{3,1}{1,7}+\frac{6,7}{5,1}=\frac{31}{17}+\frac{67}{51}=\frac{93+67}{51}=\frac{160}{51}=3\frac{7}{51}\).
б) \(\frac{2,5}{4,4}+\frac{4,6}{13,2}=\frac{25}{44}+\frac{46}{132}=\frac{75+46}{132}=\frac{11}{12}\).
в) \(\frac{6,8}{7,2}-\frac{2,7}{3,6}=\frac{17}{18}-\frac{3}{4}=\frac{7}{36}\).
г) \(\frac{2,4}{7,7}-\frac{2,8}{12,1}=\frac{24}{77}-\frac{28}{121}=\frac{68}{847}\).
Ответ: а) \(3\frac{7}{51}\); б) \(\frac{11}{12}\); в) \(\frac{7}{36}\); г) \(\frac{68}{847}\).
