а) \(2 \cos 60^\circ + \sqrt{3} \cos 30^\circ\) = \(2 \cdot \frac{1}{2} + \sqrt{3} \cdot \frac{\sqrt{3}}{2} = 1 + \frac{3}{2} = \frac{5}{2} = 2.5\)
б) \(5 \sin 30^\circ - \text{ctg} 45^\circ\) = \(5 \cdot \frac{1}{2} - 1 = \frac{5}{2} - 1 = \frac{3}{2} = 1.5\)
в) \(3 \text{tg} 45^\circ \cdot \text{tg} 60^\circ\) = \(3 \cdot 1 \cdot \sqrt{3} = 3\sqrt{3}\)
Ответы:
a) 2.5
б) 1.5
в) \(3\sqrt{3}\)