2) \(\sqrt{\dfrac{1}{16}}+\sqrt{\dfrac{25}{36}}\)

\(\sqrt{\dfrac{1}{16}}=\dfrac{1}{4}\), \(\sqrt{\dfrac{25}{36}}=\dfrac{5}{6}\).

\(\dfrac{1}{4}+\dfrac{5}{6}=\dfrac{3}{12}+\dfrac{10}{12}=\dfrac{13}{12}\).

Ответ: \(\dfrac{13}{12}\).