Ответ:
- \(\sqrt{9}\cdot\sqrt{121}=3\cdot11=33\).
- \(\sqrt{25}:\sqrt{400}=5:20=\frac{1}{4}\).
- \(\sqrt{0{,}01}-\sqrt{0{,}36}=0{,}1-0{,}6=-0{,}5\).
- \((\sqrt{9})^2-7{,}5=9-7{,}5=1{,}5\).
- \(6\left(\sqrt{\frac{5}{6}}\right)^2=6\cdot\frac{5}{6}=5\).
- \(\sqrt{5^2+24}=\sqrt{25+24}=\sqrt{49}=7\).
- \(\sqrt{10^2-4\cdot3^2}=\sqrt{100-36}=\sqrt{64}=8\).
