№2. Вычислите: а) \(\frac{\sqrt2}{\sqrt{50}}\); б) \(\frac{\sqrt{75}}{\sqrt{192}}\); в) \(\sqrt{63}\cdot\sqrt7\); г) \(\sqrt{10}\cdot\sqrt{90}\); д) \(\sqrt{25^2-24^2}\).

1. \(\frac{\sqrt2}{\sqrt{50}}=\sqrt{\frac{2}{50}}=\sqrt{\frac{1}{25}}=\frac15\).
2. \(\frac{\sqrt{75}}{\sqrt{192}}=\sqrt{\frac{75}{192}}=\sqrt{\frac{25}{64}}=\frac58\).
3. \(\sqrt{63}\cdot\sqrt7=\sqrt{441}=21\).
4. \(\sqrt{10}\cdot\sqrt{90}=\sqrt{900}=30\).
5. \(\sqrt{25^2-24^2}=\sqrt{(25-24)(25+24)}=\sqrt{49}=7\).

Ответ: а) \(\frac15\); б) \(\frac58\); в) 21; г) 30; д) 7.