Ответ:Период 3: \(0,(3)=\frac{3}{9}=\frac{1}{3}\).Период 6: \(0,(6)=\frac{6}{9}=\frac{2}{3}\).\(1,(4)=1+\frac{4}{9}=\frac{13}{9}\).\(2,1(6)=2+\frac{16-1}{90}=2+\frac{1}{6}=\frac{13}{6}\).\(5,(27)=5+\frac{27}{99}=5+\frac{3}{11}=\frac{58}{11}\).