a) \(4\frac{14}{19} - 2\frac{5}{19} = (4-2) + \frac{14-5}{19} = 2\frac{9}{19}\)
б) \(8\frac{7}{10} - 5 = 3\frac{7}{10}\)
в) \(12 - \frac{7}{18} = 11\frac{18}{18} - \frac{7}{18} = 11\frac{11}{18}\)
г) \(11 - 3\frac{5}{12} = 10\frac{12}{12} - 3\frac{5}{12} = 7\frac{7}{12}\)
д) \(8\frac{7}{15} - 3\frac{11}{15} = 7\frac{22}{15} - 3\frac{11}{15} = (7-3) + \frac{22-11}{15} = 4\frac{11}{15}\)
e) \(10\frac{9}{14} - 3\frac{9}{14} = (10-3) + \frac{9-9}{14} = 7\frac{0}{14} = 7\)
Ответы:
a) \(2\frac{9}{19}\), б) \(3\frac{7}{10}\), в) \(11\frac{11}{18}\), г) \(7\frac{7}{12}\), д) \(4\frac{11}{15}\), e) 7