3) $6\frac{2}{5}\cdot 1\frac{9}{16}-\left(2\frac{1}{4}\right)^2$

Question

Вопрос: $Фото задания: 3) $6\frac{2}{5}\cdot 1\frac{9}{16}-\left(2\frac{1}{4}\right)^2$$ Фото задания

Accepted Answer

Преобразуем смешанные числа:

$6\frac{2}{5}=\frac{32}{5}$, $1\frac{9}{16}=\frac{25}{16}$, $2\frac{1}{4}=\frac{9}{4}$.

$\frac{32}{5}\cdot\frac{25}{16}=10$.

$\left(\frac{9}{4}\right)^2=\frac{81}{16}$.

$10-\frac{81}{16}=\frac{160-81}{16}=\frac{79}{16}=4\frac{15}{16}$.

Ответ: $4\frac{15}{16}$.

3) \(6\frac{2}{5}\cdot 1\frac{9}{16}-\left(2\frac{1}{4}\right)^2\)