Ответ:

  1. а) \(\frac{c-2+3c}{3(c+4)}=\frac{4c-2}{3(c+4)}=\frac{2(2c-1)}{3(c+4)}\).
  2. б) \(\frac{b-2}{2(b-3)}-\frac{b-1}{3(b-3)}=\frac{3b-6-2b+2}{6(b-3)}=\frac{b-4}{6(b-3)}\).
  3. в) \(\frac{4a}{3(a-2)}+\frac{3a}{4(2-a)}=\frac{4a}{3(a-2)}-\frac{3a}{4(a-2)}=\frac{16a-9a}{12(a-2)}=\frac{7a}{12(a-2)}\).