№36. \(8\sin\dfrac{25\pi}{12}\cdot\cos\dfrac{25\pi}{12}\)

По формуле \(2\sin x\cos x=\sin2x\):

\(8\sin x\cos x=4\sin2x=4\sin\dfrac{25\pi}{6}=4\sin\dfrac{\pi}{6}=2\).

Ответ: 2.