37) \(\frac4{x-3}-\frac1{x+3}\)

\(\frac{4(x+3)-(x-3)}{(x-3)(x+3)}=\frac{3x+15}{x^2-9}=\frac{3(x+5)}{x^2-9}\).

Ответ: \(\frac{3(x+5)}{x^2-9}\).