Ответ:

а) \(4\frac{11}{18}\cdot\frac{6}{7}-1\frac{4}{9}=\frac{83}{18}\cdot\frac{6}{7}-\frac{13}{9}=\frac{83}{21}-\frac{13}{9}=\frac{249-91}{63}=2\frac{32}{63}\).

б) \(\left(1\frac{1}{2}\right)^3-2\frac{1}{4}\cdot1\frac{1}{3}=\frac{27}{8}-\frac{9}{4}\cdot\frac{4}{3}=\frac{27}{8}-3=\frac{3}{8}\).

в) \(\left(\left(1\frac{1}{4}\right)^2-\frac{5}{8}\right)\cdot10\frac{2}{3}-7\frac{1}{3}=\left(\frac{25}{16}-\frac{10}{16}\right)\cdot\frac{32}{3}-\frac{22}{3}=10-\frac{22}{3}=\frac{8}{3}=2\frac{2}{3}\).

г) \(1\frac{4}{9}+2\frac{5}{6}-2\frac{3}{4}=\frac{52+102-99}{36}=\frac{55}{36}\), а \(2\frac{1}{2}-\frac{11}{14}=\frac{12}{7}\). Следовательно, \(\frac{55}{36}\cdot\frac{12}{7}=\frac{55}{21}=2\frac{13}{21}\).

Ответ: а) 2 32/63; б) 3/8; в) 2 2/3; г) 2 13/21.