5. Find CE, PC.

To solve this problem, we need more information about the triangle PKЕ. Specifically, we need either lengths of sides or values of angles other than ∠KPC = 150° and ∠CKP = 90°.

Assuming that:

• Triangle PKC is a right-angled triangle with ∠CKP = 90°.
• ∠CPK = 180° - 150° = 30° (since ∠CPK and ∠KPC are supplementary angles).
• In right-angled triangle PKC, ∠PCK = 180° - 90° - 30° = 60°.
• We are given KE = 9.

However, without knowing any side lengths of triangle PKC or any information about triangle CKE, we cannot determine CE and PC.

If we assume that KE = 9 is a side length of triangle CKE, and that CK is perpendicular to PE, then:

If triangle CKE is a right-angled triangle with ∠CKE = 90°, and we knew CE or KE, we could find CK and PE.

If there is additional information or a diagram with more details, please provide it.

Answer: Insufficient information to solve for CE and PC.