а) Решим уравнение $$\frac{4x + 8}{3} - \frac{2x - 3}{4} = 1$$:
\[ 12 \left( \frac{4x + 8}{3} \right) - 12 \left( \frac{2x - 3}{4} \right) = 12(1) \]
\[ 4(4x + 8) - 3(2x - 3) = 12 \]
\[ (16x + 32) - (6x - 9) = 12 \]
\[ 16x + 32 - 6x + 9 = 12 \]
\[ (16x - 6x) + (32 + 9) = 12 \]
\[ 10x + 41 = 12 \]
\[ 10x = 12 - 41 \]
\[ 10x = -29 \]
\[ x = \frac{-29}{10} \]
\[ x = -2.9 \]
б) Решим уравнение $$5x - 6x^2 = 0$$:
\[ x(5 - 6x) = 0 \]
Решим второе уравнение:
\[ 5 = 6x \]
\[ x = \frac{5}{6} \]
Ответ: а) $$x = -2.9$$; б) $$x = 0$$, $$x = \frac{5}{6}$$