\(2\sqrt{5}( \sqrt{20}-3\sqrt{5} )\) = \(2\sqrt{5}(2\sqrt{5}-3\sqrt{5})\) = \(2\sqrt{5} \cdot (-\sqrt{5})\) = \(-2 \cdot 5 = -10\)
\((3+2\sqrt{7})^2\) = \(3^2 + 2 \cdot 3 \cdot 2\sqrt{7} + (2\sqrt{7})^2\) = \(9 + 12\sqrt{7} + 28\) = \(37 + 12\sqrt{7}\)
\((\sqrt{11}+2\sqrt{5})(\sqrt{11}-2\sqrt{5})\) = \((\sqrt{11})^2 - (2\sqrt{5})^2\) = \(11 - 20 = -9\)
Ответ: 6) -10; в) 37 + 12√7; г) -9.