6. Найдите значение числового выражения: а) \((8\frac{7}{12}-2\frac{17}{36})\cdot2,7-4\frac13:0,65\); б) \((1\frac{11}{24}+\frac{13}{36})\cdot1,44-\frac{8}{15}\cdot0,5625\); в) \((6\frac{8}{15}-4\frac{21}{45})\cdot4,5-2\frac16:0,52\); г) \((\frac{9}{22}+1\frac{12}{33})\cdot1,32-\frac{8}{13}\cdot0,1625\).

а) \((8\frac{7}{12}-2\frac{17}{36})=\frac{55}{9}\), поэтому \(\frac{55}{9}\cdot\frac{27}{10}-\frac{13}{3}:\frac{13}{20}=\frac{33}{2}-\frac{20}{3}=\frac{59}{6}\).

б) \((1\frac{11}{24}+\frac{13}{36})\cdot1,44-\frac{8}{15}\cdot0,5625=\frac{131}{72}\cdot\frac{36}{25}-\frac{3}{10}=\frac{58}{25}\).

в) \((6\frac{8}{15}-4\frac{21}{45})\cdot4,5-2\frac16:0,52=\frac{2}{15}\cdot\frac92-\frac{13}{6}:\frac{13}{25}=\frac35-\frac{25}{6}=-\frac{107}{30}\).

г) \((\frac{9}{22}+1\frac{12}{33})\cdot1,32-\frac{8}{13}\cdot0,1625=\frac{24}{11}\cdot\frac{33}{25}-\frac{1}{10}=\frac{139}{50}\).

Ответ: а) \(\frac{59}{6}\); б) \(\frac{58}{25}\); в) \(-\frac{107}{30}\); г) \(\frac{139}{50}\).