Ответ:
а) \(\sin 240^\circ=\sin(180^\circ+60^\circ)=-\sin 60^\circ=-\frac{\sqrt{3}}{2}\).
б) \(\operatorname{tg}300^\circ=\operatorname{tg}(360^\circ-60^\circ)=-\operatorname{tg}60^\circ=-\sqrt{3}\).
в) \(\cos 330^\circ=\cos(360^\circ-30^\circ)=\cos 30^\circ=\frac{\sqrt{3}}{2}\).
г) \(\operatorname{ctg}315^\circ=\operatorname{ctg}(360^\circ-45^\circ)=-\operatorname{ctg}45^\circ=-1\).
