1436. a) log 1/2 1; 6) log0.5 1/4√2 ;

1436.

1. a) $$log_{\frac{1}{2}} 1 = 0$$
2. б) $$log_{0.5} \frac{1}{4\sqrt{2}} = log_{\frac{1}{2}} \frac{1}{2^2 \cdot 2^{1/2}} = log_{\frac{1}{2}} \frac{1}{2^{5/2}} = log_{2^{-1}} 2^{-5/2} = \frac{5}{2}$$

Ответ: а) 0; б) $$\frac{5}{2}$$