1435. b) log√2 49, 6) logs (2√8);

1435.

1. a) $$log_{\sqrt{2}} 49 = log_{2^{1/2}} 7^2 = 2 \cdot 2 log_2 7 = 4log_2 7$$
2. б) $$log_{\sqrt{2}} (2\sqrt{8}) = log_{\sqrt{2}} (2\sqrt{2^3}) = log_{\sqrt{2}} (2 \cdot 2^{3/2}) = log_{\sqrt{2}} (2^{5/2}) = log_{2^{1/2}} 2^{5/2} = \frac{5}{2} \cdot 2 log_2 2 = 5$$

Ответ: a) $$4log_2 7$$, б) 5