B) 34log3 2, r) 5-2logs 3

1. в) $$3^{4log_3 2} = (3^{log_3 2})^4 = 2^4 = 16$$
2. г) $$5^{-2log_5 3} = \frac{1}{5^{2log_5 3}} = \frac{1}{(5^{log_5 3})^2} = \frac{1}{3^2} = \frac{1}{9}$$

Ответ: в) 16, г) $$\frac{1}{9}$$