1497. a) log144 3 + log144 4; 6) lg 40+ lg 25;

1497. Вычислите:

a) $$log_{144} 3 + log_{144} 4 = log_{144} (3 \cdot 4) = log_{144} 12 = log_{12^2} 12 = \frac{1}{2}log_{12} 12 = \frac{1}{2}$$

б) $$lg 40 + lg 25 = lg (40 \cdot 25) = lg 1000 = lg 10^3 = 3$$

Ответ: a) $$\frac{1}{2}$$, б) 3