Ответ:
При \(c=-3\):
\[\frac{3c-5}{4-c^2}+\frac{3-2c}{c^2-4}=\frac{-14}{-5}+\frac{9}{5}=\frac{14}{5}+\frac{9}{5}=\frac{23}{5}.\]
Ответ: \(\frac{23}{5}\).
При \(c=-3\):
\[\frac{3c-5}{4-c^2}+\frac{3-2c}{c^2-4}=\frac{-14}{-5}+\frac{9}{5}=\frac{14}{5}+\frac{9}{5}=\frac{23}{5}.\]
Ответ: \(\frac{23}{5}\).