б) \(5\frac{4}{7}:1\frac{5}{21}-\left(5\frac{2}{15}\cdot\frac{3}{22}+1\frac{14}{15}\right)\)

Выполняем деление и умножение:

\(5\frac{4}{7}:1\frac{5}{21}=\frac{39}{7}:\frac{26}{21}=\frac{39}{7}\cdot\frac{21}{26}=\frac{9}{2}\).

В скобках: \(5\frac{2}{15}\cdot\frac{3}{22}=\frac{77}{15}\cdot\frac{3}{22}=\frac{7}{10}\), а \(1\frac{14}{15}=\frac{29}{15}\).

\(\frac{7}{10}+\frac{29}{15}=\frac{21}{30}+\frac{58}{30}=\frac{79}{30}\).

\(\frac{9}{2}-\frac{79}{30}=\frac{135}{30}-\frac{79}{30}=\frac{56}{30}=1\frac{13}{15}\).

Ответ: \(1\frac{13}{15}\).