Ответ:Решение:\( \frac{5}{7}y + \frac{2}{3}y = 4 + \frac{1}{7} \)\( \frac{15+14}{21}y = \frac{28+1}{7} \)\( \frac{29}{21}y = \frac{29}{7} \)\( y = \frac{29}{7} \cdot \frac{21}{29} \)\( y = 3 \)Ответ: \( y = 3 \).