B2. 1) ∠AOB = 160°, 5∠BOC = 3∠AOC, ∠AOC, ∠BOC - ?

Question

Вопрос:

B2. 1) ∠AOB = 160°, 5∠BOC = 3∠AOC, ∠AOC, ∠BOC - ?

Accepted Answer

1. ∠AOB = 160°. 5∠BOC = 3∠AOC. Let ∠BOC = 3x, then ∠AOC = 5x.
2. ∠AOB = ∠AOC + ∠BOC.
3. 160° = 5x + 3x. 160° = 8x. x = 20°. ∠BOC = 3 * 20° = 60°, ∠AOC = 5 * 20° = 100°.

B2. 1) ∠AOB = 160°, 5∠BOC = 3∠AOC, ∠AOC, ∠BOC - ?

Ответ: