B3. 2) ∠FOE = 140°, ∠POK + ∠KOE = 3∠POK - ∠KOE + 20°, ∠FOK, ∠KOE - ?

1. ∠FOE = 140°. ∠POK + ∠KOE = 3∠POK - ∠KOE + 20°. 2∠KOE = 2∠POK + 20°. ∠KOE = ∠POK + 10°.
2. ∠FOE = ∠FOK + ∠KOE. 140° = ∠FOK + ∠KOE.
3. ∠FOK = ∠FOE - ∠KOE = 140° - ∠KOE. Substitute into the equation from step 1: ∠KOE = (140° - ∠KOE) + 10°. 2∠KOE = 150°. ∠KOE = 75°. ∠FOK = 140° - 75° = 65°.