B3. 1) ∠MOK = 150°, ∠KON - ∠MON = 70°, ∠MON, ∠KON - ?

Question

Вопрос:

B3. 1) ∠MOK = 150°, ∠KON - ∠MON = 70°, ∠MON, ∠KON - ?

Accepted Answer

1. ∠MOK = 150°. ∠KON - ∠MON = 70°. ∠KON = ∠MON + 70°.
2. ∠MOK = ∠MON + ∠KON.
3. 150° = ∠MON + (∠MON + 70°). 150° = 2∠MON + 70°. 2∠MON = 80°. ∠MON = 40°, ∠KON = 40° + 70° = 110°.

B3. 1) ∠MOK = 150°, ∠KON - ∠MON = 70°, ∠MON, ∠KON - ?

Ответ: