1154. Чему равен корень уравнения: 1) $$\frac{x-8}{x+2} = \frac{7}{3}$$; 2) $$\frac{4}{x-1,2} = \frac{15}{x-10}$$?

Решение: 1) $$\frac{x-8}{x+2} = \frac{7}{3}$$ $$3(x-8) = 7(x+2)$$ $$3x - 24 = 7x + 14$$ $$3x - 7x = 14 + 24$$ $$-4x = 38$$ $$x = -\frac{38}{4} = -\frac{19}{2} = -9,5$$ Ответ: x = -9,5 2) $$\frac{4}{x-1,2} = \frac{15}{x-10}$$ $$4(x-10) = 15(x-1,2)$$ $$4x - 40 = 15x - 18$$ $$4x - 15x = -18 + 40$$ $$-11x = 22$$ $$x = -2$$ Ответ: x = -2