д) у² - 52у - 576; e) 15y² - 30 = 22y + 7; ж) 25р² = 10p - 1; 3) 299x² + 100x = 500 - 101x².

Решим уравнения:

1. д) $$y^2 - 52y - 576 = 0$$
   $$D = (-52)^2 - 4 \cdot 1 \cdot (-576) = 2704 + 2304 = 5008$$
   $$y_1 = \frac{52 + \sqrt{5008}}{2 \cdot 1} = \frac{52 + 4\sqrt{313}}{2} = 26 + 2\sqrt{313}$$
   $$y_2 = \frac{52 - \sqrt{5008}}{2 \cdot 1} = \frac{52 - 4\sqrt{313}}{2} = 26 - 2\sqrt{313}$$
   Ответ: $$y_1 = 26 + 2\sqrt{313}$$, $$y_2 = 26 - 2\sqrt{313}$$
2. е) $$15y^2 - 30 = 22y + 7$$
   $$15y^2 - 22y - 37 = 0$$
   $$D = (-22)^2 - 4 \cdot 15 \cdot (-37) = 484 + 2220 = 2704$$
   $$y_1 = \frac{22 + \sqrt{2704}}{2 \cdot 15} = \frac{22 + 52}{30} = \frac{74}{30} = \frac{37}{15}$$
   $$y_2 = \frac{22 - \sqrt{2704}}{2 \cdot 15} = \frac{22 - 52}{30} = \frac{-30}{30} = -1$$
   Ответ: $$y_1 = \frac{37}{15}$$, $$y_2 = -1$$
3. ж) $$25p^2 = 10p - 1$$
   $$25p^2 - 10p + 1 = 0$$
   $$D = (-10)^2 - 4 \cdot 25 \cdot 1 = 100 - 100 = 0$$
   $$p = \frac{10 + \sqrt{0}}{2 \cdot 25} = \frac{10}{50} = \frac{1}{5}$$
   Ответ: $$p = \frac{1}{5}$$
4. з) $$299x^2 + 100x = 500 - 101x^2$$
   $$400x^2 + 100x - 500 = 0$$
   $$4x^2 + x - 5 = 0$$
   $$D = 1^2 - 4 \cdot 4 \cdot (-5) = 1 + 80 = 81$$
   $$x_1 = \frac{-1 + \sqrt{81}}{2 \cdot 4} = \frac{-1 + 9}{8} = \frac{8}{8} = 1$$
   $$x_2 = \frac{-1 - \sqrt{81}}{2 \cdot 4} = \frac{-1 - 9}{8} = \frac{-10}{8} = -\frac{5}{4}$$
   Ответ: $$x_1 = 1$$, $$x_2 = -\frac{5}{4}$$