два раза выпало меньше пяти очков;

Let A be the event that the outcome of a single roll is less than 5 (i.e., 1, 2, 3, or 4). P(A) = 4/6 = 2/3. We want to find the probability that both rolls are less than 5, given that the sum is less than 7. The outcomes where both rolls are less than 5 are: (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1). There are 10 such outcomes. The probability is 10/15 = 2/3.