Преобразуем смешанные числа в неправильные дроби:
3 \(\frac{2}{3}\) = \(\frac{3*3 + 2}{3}\) = \(\frac{11}{3}\)
1 \(\frac{2}{7}\) = \(\frac{1*7 + 2}{7}\) = \(\frac{9}{7}\)
5 \(\frac{4}{9}\) = \(\frac{5*9 + 4}{9}\) = \(\frac{49}{9}\)
Подставим в выражение:
\(\frac{11}{3} - \frac{9}{7} * \frac{49}{9}\) : (-2,5) = \(\frac{11}{3} - \frac{9*49}{7*9}\) : (-2,5) = \(\frac{11}{3} - \frac{1*7}{1*1}\) : (-2,5) = \(\frac{11}{3} - 7\) : (-2,5)
Приведем дроби к общему знаменателю (3):
\(\frac{11}{3} - \frac{7*3}{1*3}\) : (-2,5) = \(\frac{11}{3} - \frac{21}{3}\) : (-2,5) = -\(\frac{10}{3}\) : (-2,5) = -\(\frac{10}{3}\) : \(- \frac{5}{2}\) = -\(\frac{10}{3}\) * \(- \frac{2}{5}\) = \(\frac{10*2}{3*5}\) = \(\frac{2*2}{3*1}\) = \(\frac{4}{3}\) = 1 \(\frac{1}{3}\)
Ответ: 1 \(\frac{1}{3}\)